Question 1: What is the net of a cuboid with length 4 cm, width 3 cm, and height 2 cm? Sketch and label all faces.

Answer: Net diagram with 6 rectangles: 2 of 4x3, 2 of 3x2, 2 of 4x2

Question 2: Calculate the total surface area of a cuboid measuring 5 cm by 3 cm by 2 cm.

Answer: 2(5×3 + 3×2 + 5×2) = 2(15 + 6 + 10) = 2(31) = 62 cm²

Question 3: Draw a net for a cuboid with dimensions 6 cm by 4 cm by 3 cm.

Answer: Net with rectangles measuring 6x4, 6x3, 4x3 arranged appropriately.

Question 4: A net of a cuboid is shown with face dimensions 8 cm by 3 cm, and 6 cm by 3 cm. If the total surface area is 132 cm², what are the missing face dimensions?

Answer: Remaining faces are 8x6 and 8x3; calculations confirm total area.

Question 5: Construct a net for a cuboid with a base of 7 cm by 5 cm and height 4 cm.

Answer: Net with rectangles: 7x5 (base), 7x4, 5x4 (sides).

Question 6: Calculate the surface area of a cube with edge length 6 cm.

Answer: 6×6×6=216; Surface area=6×(6²)=216 cm²

Question 7: A student draws a net that omits one face of a cuboid. What effect does this have on the surface area calculation?

Answer: Surface area would be underestimated; all faces must be included.

Question 8: Given a cuboid with dimensions 9 cm by 4 cm by 2 cm, find the difference in surface area if the height is increased to 5 cm.

Answer: Original SA=2(9×4+4×2+9×2)=2(36+8+18)=2(62)=124 cm²; New SA=2(36+4×5+9×5)=2(36+20+45)=2(101)=202 cm²; Difference=202-124=78 cm²

Question 9: Identify the common mistake made when calculating surface area from a net and explain how to avoid it.

Answer: Omitting faces or double counting; carefully check all faces and ensure each is only counted once.

Question 10: A cuboid has a net with faces measuring 10 cm by 4 cm, 10 cm by 6 cm, and 4 cm by 6 cm. Calculate its surface area.

Answer: 2(10×4 + 10×6 + 4×6)=2(40+60+24)=2(124)=248 cm²