Question 1: Calculate the acceleration of a car that increases its velocity from 0 m/s to 20 m/s in 5 seconds.

Answer: 4

Question 2: A velocity-time graph shows a straight line rising from 10 m/s to 30 m/s over 4 seconds. What is the acceleration?

Answer: 5

Question 3: Construct a velocity-time graph segment depicting constant acceleration of 3 m/s² over a 6-second interval. Label initial and final velocities.

Answer: Initial velocity 0 m/s, final velocity 18 m/s

Question 4: Explain why a horizontal line on a velocity-time graph indicates zero acceleration.

Answer: Because the velocity remains constant, meaning no change over time, so acceleration is zero.

Question 5: A cyclist accelerates uniformly from 5 m/s to 15 m/s over 10 seconds. What is their acceleration?

Answer: 1

Question 6: On a velocity-time graph, a line slopes downward from 20 m/s to 0 m/s in 4 seconds. What is the acceleration?

Answer: -5

Question 7: A car's velocity increases from 0 to 25 m/s in 5 seconds, then decreases back to 0 in the next 5 seconds. Describe the acceleration during each phase.

Answer: During acceleration, the acceleration is +5 m/s²; during deceleration, it is -5 m/s².

Question 8: Identify the common mistake in interpreting a velocity-time graph with a curved line representing acceleration.

Answer: A common mistake is assuming the acceleration is constant when the curve indicates changing acceleration.

Question 9: A velocity-time graph shows a line with a slope of 2 m/s². If the initial velocity is 0 m/s, what is the velocity after 8 seconds?

Answer: 16

Question 10: A vehicle accelerates at 3 m/s² for 12 seconds starting from rest. Plot the velocity at 0, 4, 8, and 12 seconds on the grid. Describe the pattern.

Answer: Velocities: 0, 12, 24, 36 m/s. The pattern is linear increase, indicating constant acceleration.

Question 11: A student incorrectly calculates average acceleration as (final velocity - initial velocity) / total time, but the velocity was not changing uniformly. Explain why this is incorrect.

Answer: Because average acceleration assumes uniform change, which is not true if the velocity changes non-linearly.

Question 12: Given the velocity-time graph with a line sloping upward then downward, identify the segments of acceleration and deceleration and their respective slopes.

Answer: The upward segment has a positive slope indicating acceleration; the downward segment has a negative slope indicating deceleration.