Question 1: Elastic energy is the potential energy stored when an object is stretched or compressed. This energy is released when the object returns to its original shape.

Answer: Elastic energy is the potential energy stored in an object when it is deformed elastically (stretched or compressed) and is released when the object returns to its original shape.

Question 1: Define elastic potential energy.

Answer: Elastic potential energy is the energy stored in an object when it is stretched or compressed and can do work when released.

Question 2: Explain the mechanism by which a stretched rubber band stores elastic energy.

Answer: When a rubber band is stretched, work is done to deform it, and this work is stored as elastic potential energy within the stretched material. When released, this stored energy causes the rubber band to snap back to its original shape.

Question 1: A spring has a spring constant of 200 N/m and is stretched by 0.05 meters. Calculate the elastic potential energy stored in the spring.

Answer: E = 0.5 × 200 N/m × (0.05 m)² = 0.5 × 200 × 0.0025 = 0.25 Joules

Question 2: A bungee cord acts like a spring with a spring constant of 150 N/m. If a person stretches the cord by 0.2 meters during a jump, how much elastic energy is stored?

Answer: E = 0.5 × 150 N/m × (0.2 m)² = 0.5 × 150 × 0.04 = 3 Joules

Question 1: Describe a simple experiment to demonstrate elastic energy storage using a rubber band and a ruler.

Answer: Stretch a rubber band by a measured length using a ruler and release it. Observe how the rubber band snaps back to its original shape, demonstrating elastic energy release. Ensure safety by avoiding overstretching to prevent snapping or injury.

Question 2: Identify two variables that affect the amount of elastic energy stored in a stretched spring or elastic material.

Answer: The extension (x) of the spring and the spring constant (k) of the material.

Question 1: A steel spring with a spring constant of 300 N/m is stretched by 0.04 meters. The elastic potential energy stored is measured as 24 Joules. Verify this calculation and explain any discrepancy.

Answer: Using the formula: E = 0.5 × k × x² = 0.5 × 300 × (0.04)² = 0.5 × 300 × 0.0016 = 0.24 Joules. The calculated energy is 0.24 Joules, which does not match the given 24 Joules, indicating a possible error in measurement units or data recording. The discrepancy suggests the extension may have been 0.4 meters or the spring constant different.

Question 1: Describe how elastic energy is utilized in a trampoline to provide a bouncing force.

Answer: When a person jumps on a trampoline, the flexible surface stretches and stores elastic potential energy. As it returns to its original shape, this stored energy propels the person upward, enabling bouncing.

Question 2: Explain how elastic potential energy is important in the design of safety devices like shock absorbers in vehicles.

Answer: Shock absorbers contain springs or elastic components that store elastic potential energy when compressed. This energy absorption reduces the impact force transmitted to the vehicle and passengers, improving safety and ride comfort.