Question 1: Explain what a velocity-time graph represents and how it can be used to analyse the motion of an object.

Answer: A velocity-time graph displays how an object's velocity changes over time. It is used to determine acceleration, constant velocity, and displacement by analysing the shape and area under the graph.

Question 1: Define acceleration in the context of a velocity-time graph.

Answer: Acceleration is the rate of change of velocity with respect to time, represented by the gradient (slope) of the velocity-time graph.

Question 2: What does a horizontal line on a velocity-time graph indicate about the motion of the object?

Answer: It indicates that the object is moving at a constant velocity, with no acceleration.

Question 1: A car accelerates uniformly from 0 m/s to 20 m/s over 10 seconds. Calculate its acceleration in m/s².

Answer: Acceleration = (Final velocity - Initial velocity) / Time = (20 m/s - 0 m/s) / 10 s = 2 m/s²

Question 2: A cyclist maintains a constant velocity of 15 m/s for 30 seconds. How far does the cyclist travel in that time?

Answer: Distance = Velocity × Time = 15 m/s × 30 s = 450 metres

Question 3: During a particular period, an object's velocity increases from 5 m/s to 15 m/s in 4 seconds. What is the average acceleration?

Answer: Average acceleration = (15 m/s - 5 m/s) / 4 s = 2.5 m/s²

Question 1: Describe a simple experiment to measure the velocity of a toy car over a straight track. Include the variables involved and safety precautions.

Answer: Set up a straight track with a toy car. Use a stopwatch to measure the time taken to travel specific distances. Variables include initial speed, acceleration, and timing accuracy. Safety precautions involve ensuring the track is stable, the area is clear of obstructions, and handling the stopwatch carefully to avoid injury or inaccurate readings.

Question 1: A velocity-time graph shows a straight line sloping upwards from 0 m/s at 0 seconds to 10 m/s at 5 seconds. What is the acceleration of the object? How much displacement does it cover in this time?

Answer: The acceleration is (Change in velocity) / (Time) = (10 m/s - 0 m/s) / 5 s = 2 m/s². Displacement = Area under the graph = (1/2) × base × height = (1/2) × 5 s × 10 m/s = 25 metres.

Question 2: A vehicle moves at a constant velocity for 20 seconds, then suddenly decelerates uniformly to a stop over 10 seconds. Describe how the velocity-time graph would look and what information can be obtained from it.

Answer: The graph would show a horizontal line at constant velocity followed by a downward sloping line to zero velocity. From it, you can determine the constant speed, deceleration rate, and total displacement during both phases.

Question 1: Explain how velocity-time graphs are used in analysing vehicle motion in traffic safety testing.

Answer: Velocity-time graphs help assess acceleration and deceleration patterns, ensuring vehicles meet safety standards by analysing their responses during braking and acceleration in controlled tests.

Question 2: Describe a scenario in sports where understanding velocity-time graphs could improve performance or safety.

Answer: In sprinting, analysing velocity-time data helps athletes optimise their acceleration phases for better performance and reduce injury risk by monitoring acceleration patterns.